Completing the square is a powerful technique for solving quadratic equations. It transforms a quadratic expression into a perfect square trinomial, making it easier to find solutions. This method is especially useful when dealing with equations that can't be easily factored.
By mastering completing the square, you'll gain a deeper understanding of quadratic relationships. It's not just about finding solutions โ it also reveals the vertex form of quadratic functions, which is crucial for graphing and analyzing parabolas.
Completing the Square
Binomial to perfect square trinomial
- Binomial expression in the form $ax^2 + bx$
- $a$ represents coefficient of $x^2$ term
- $b$ represents coefficient of $x$ term
- Transform binomial into perfect square trinomial by adding square of half the coefficient of $x$ to both sides of equation
- Calculate $(\frac{b}{2})^2$ and add to both sides
- Resulting trinomial on left side will be perfect square in the form $(ax + \frac{b}{2})^2$
- Example: $x^2 + 6x$ becomes $(x + 3)^2$ by adding $(\frac{6}{2})^2 = 3^2 = 9$ to both sides
Completing the square with coefficient 1
- Quadratic equation in standard form $x^2 + bx + c = 0$, where leading coefficient $a = 1$
- Isolate variable terms on one side by subtracting $c$ from both sides
- $x^2 + bx = -c$
- Transform binomial $x^2 + bx$ into perfect square trinomial
- Add $(\frac{b}{2})^2$ to both sides of equation
- Left side becomes $(x + \frac{b}{2})^2 = -c + (\frac{b}{2})^2$
- Take square root of both sides
- $x + \frac{b}{2} = \pm \sqrt{-c + (\frac{b}{2})^2}$
- Solve for $x$ by subtracting $\frac{b}{2}$ from both sides
- $x = -\frac{b}{2} \pm \sqrt{-c + (\frac{b}{2})^2}$
- Example: $x^2 + 6x + 5 = 0$ becomes $x = -3 \pm \sqrt{-5 + (\frac{6}{2})^2} = -3 \pm \sqrt{4} = -3 \pm 2$, so $x = -5$ or $x = -1$
Completing the square for any coefficient
- Quadratic equation in standard form $ax^2 + bx + c = 0$, where leading coefficient $a \neq 1$
- Divide both sides by $a$ to make leading coefficient 1
- $x^2 + \frac{b}{a}x + \frac{c}{a} = 0$
- Isolate variable terms on one side by subtracting $\frac{c}{a}$ from both sides
- $x^2 + \frac{b}{a}x = -\frac{c}{a}$
- Transform binomial $x^2 + \frac{b}{a}x$ into perfect square trinomial
- Add $(\frac{b}{2a})^2$ to both sides of equation
- Left side becomes $(x + \frac{b}{2a})^2 = -\frac{c}{a} + (\frac{b}{2a})^2$
- Take square root of both sides
- $x + \frac{b}{2a} = \pm \sqrt{-\frac{c}{a} + (\frac{b}{2a})^2}$
- Solve for $x$ by subtracting $\frac{b}{2a}$ from both sides
- $x = -\frac{b}{2a} \pm \sqrt{-\frac{c}{a} + (\frac{b}{2a})^2}$
- Example: $2x^2 + 12x + 7 = 0$ becomes $x = -\frac{12}{2(2)} \pm \sqrt{-\frac{7}{2} + (\frac{12}{2(2)})^2} = -3 \pm \sqrt{\frac{1}{2}} = -3 \pm \frac{\sqrt{2}}{2}$
Other Methods for Solving Quadratic Equations
- Factoring: Useful when the quadratic expression can be easily factored
- Quadratic formula: An alternative method derived from completing the square
- Discriminant: Helps determine the nature of roots (real or complex) without solving the equation
- For $ax^2 + bx + c = 0$, the discriminant is $b^2 - 4ac$
- If discriminant > 0, there are two distinct real roots
- If discriminant = 0, there is one real root (repeated)
- If discriminant < 0, there are two complex roots