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๐Ÿ”ฅThermodynamics I Unit 13 Review

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13.3 First and second-law analysis of gas mixtures

๐Ÿ”ฅThermodynamics I
Unit 13 Review

13.3 First and second-law analysis of gas mixtures

Written by the Fiveable Content Team โ€ข Last updated September 2025
Written by the Fiveable Content Team โ€ข Last updated September 2025
๐Ÿ”ฅThermodynamics I
Unit & Topic Study Guides

Gas mixtures are a crucial part of thermodynamics. The first law helps us understand energy changes in these mixtures, while the second law deals with entropy and process reversibility. These concepts are key to analyzing real-world systems involving multiple gases.

Applying these laws to gas mixtures lets us calculate work, heat transfer, and internal energy changes. We can also determine entropy changes and assess process reversibility. This knowledge is essential for designing efficient systems and understanding natural phenomena involving gas mixtures.

Thermodynamics of Ideal Gas Mixtures

First Law of Thermodynamics for Ideal Gas Mixtures

  • The first law of thermodynamics states that the change in internal energy of a system equals the heat added to the system minus the work done by the system
  • For an ideal gas mixture, the internal energy depends only on temperature and can be calculated using the specific heats of the individual components
  • The work done by an ideal gas mixture during a process can be determined using the ideal gas equation of state and the process path
  • The heat transfer during a process involving an ideal gas mixture can be calculated using the first law of thermodynamics, the change in internal energy, and the work done
  • The first law of thermodynamics applies to various processes involving ideal gas mixtures (isothermal, isobaric, isochoric, and adiabatic processes)

Analyzing Processes with Ideal Gas Mixtures

  • Apply the first law of thermodynamics to analyze processes involving ideal gas mixtures
    • Determine the change in internal energy using the specific heats and temperature change
    • Calculate the work done using the pressure-volume relationship and the process path
    • Evaluate the heat transfer using the first law, change in internal energy, and work done
  • Examples of processes involving ideal gas mixtures:
    • Isothermal process: constant temperature, heat transfer equals work done
    • Isobaric process: constant pressure, work done equals $pฮ”V$
    • Isochoric process: constant volume, no work done, heat transfer equals change in internal energy
    • Adiabatic process: no heat exchange with surroundings, work done calculated using adiabatic process equation

Work, Heat, and Internal Energy Changes

Calculating Work Done by Ideal Gas Mixtures

  • The work done by an ideal gas mixture during a process can be calculated by integrating the pressure-volume relationship along the process path
    • For a reversible isothermal process, work done equals $nRTln(V_2/V_1)$
    • For a reversible isobaric process, work done equals $p(V_2-V_1)$
    • For an isochoric process, work done is zero due to no change in volume
    • For a reversible adiabatic process, work done can be calculated using the adiabatic process equation and the specific heat ratio of the gas mixture
  • Examples of work calculations for ideal gas mixtures:
    • Isothermal expansion of a gas mixture from 1 L to 2 L at 300 K
    • Isobaric compression of a gas mixture from 2 L to 1 L at 1 atm
    • Isochoric heating of a gas mixture at constant volume
    • Adiabatic expansion of a gas mixture with a specific heat ratio of 1.4

Determining Internal Energy Changes and Heat Transfer

  • The change in internal energy of an ideal gas mixture can be determined using the specific heats of the individual components and the change in temperature
  • The heat transfer during a process involving an ideal gas mixture can be calculated using the first law of thermodynamics, the change in internal energy, and the work done
    • For an isothermal process, heat transfer equals work done because internal energy remains constant
    • For an isobaric process, heat transfer equals $mc_p(T_2-T_1)$
    • For an isochoric process, heat transfer equals change in internal energy because no work is done
    • For an adiabatic process, heat transfer is zero due to no heat exchange with the surroundings
  • Examples of internal energy and heat transfer calculations:
    • Isothermal compression of a gas mixture, determining heat transfer
    • Isobaric heating of a gas mixture, calculating change in internal energy and heat transfer
    • Isochoric cooling of a gas mixture, evaluating change in internal energy and heat transfer
    • Adiabatic compression of a gas mixture, analyzing change in internal energy and work done

Entropy Changes and Second Law Implications

Entropy Changes in Ideal Gas Mixtures

  • The second law of thermodynamics introduces entropy, a measure of the disorder or randomness of a system
  • The change in entropy of an ideal gas mixture during a process can be calculated using the specific heats of the individual components and the changes in temperature and pressure
    • For a reversible isothermal process, entropy change equals heat transfer divided by constant temperature
    • For a reversible isobaric process, entropy change can be calculated using specific heat at constant pressure and $ln(T_2/T_1)$
    • For a reversible isochoric process, entropy change can be calculated using specific heat at constant volume and $ln(T_2/T_1)$
    • For a reversible adiabatic process, entropy change is zero due to no heat transfer
  • Examples of entropy change calculations for ideal gas mixtures:
    • Reversible isothermal expansion of a gas mixture, determining entropy change
    • Reversible isobaric cooling of a gas mixture, calculating entropy change
    • Reversible isochoric heating of a gas mixture, evaluating entropy change
    • Reversible adiabatic compression of a gas mixture, analyzing entropy change

Second Law Analysis of Ideal Gas Mixture Processes

  • The second law of thermodynamics states that the total entropy of an isolated system always increases for irreversible processes and remains constant for reversible processes
  • The entropy generation during a process involving an ideal gas mixture can be used to evaluate the irreversibility of the process
    • For a reversible process, entropy generation is zero, indicating no dissipative effects
    • For an irreversible process, entropy generation is positive, indicating the presence of dissipative effects
  • Examples of second law analysis for ideal gas mixture processes:
    • Analyzing the entropy generation during the mixing of two different ideal gases
    • Evaluating the irreversibility of a throttling process (unrestrained expansion) of a gas mixture
    • Comparing the entropy changes in reversible and irreversible adiabatic expansions of a gas mixture

Reversibility vs Irreversibility of Processes

Reversible Processes

  • A reversible process can be reversed without leaving any trace on the surroundings and occurs infinitely slowly through a series of equilibrium states
  • The reversibility of a process involving an ideal gas mixture can be determined by analyzing the entropy generation during the process
    • For a reversible process, entropy generation is zero, indicating no dissipative effects (friction, heat transfer through a finite temperature difference, or unrestrained expansion)
  • The reversibility of a process can also be evaluated by examining the process path and comparing it with the corresponding reversible process
  • Examples of reversible processes involving ideal gas mixtures:
    • Reversible isothermal compression or expansion
    • Reversible isobaric heating or cooling
    • Reversible isochoric heating or cooling
    • Reversible adiabatic compression or expansion

Irreversible Processes

  • An irreversible process cannot be reversed without leaving a trace on the surroundings and occurs at a finite rate
  • The irreversibility of a process involving an ideal gas mixture can be quantified using the concept of exergy destruction, which represents the lost potential to do useful work due to entropy generation
  • Examples of irreversible processes involving ideal gas mixtures:
    • Throttling process (unrestrained expansion) of a gas mixture
    • Mixing of two different ideal gases at different temperatures or pressures
    • Heat transfer through a finite temperature difference between a gas mixture and its surroundings
    • Friction during the flow of a gas mixture through pipes or ducts
  • The irreversibility of a process can be reduced by minimizing entropy generation through the use of efficient designs, heat exchangers, and insulation