Fiveable

๐Ÿ”ทHonors Geometry Unit 13 Review

QR code for Honors Geometry practice questions

13.1 Distance and midpoint formulas

๐Ÿ”ทHonors Geometry
Unit 13 Review

13.1 Distance and midpoint formulas

Written by the Fiveable Content Team โ€ข Last updated September 2025
Written by the Fiveable Content Team โ€ข Last updated September 2025
๐Ÿ”ทHonors Geometry
Unit & Topic Study Guides

The distance and midpoint formulas are key tools for working with line segments in a coordinate plane. They help you find lengths between points and locate the center of a segment, which is super useful in geometry.

These formulas are based on the Pythagorean theorem and simple averages. You'll use them to solve real-world problems, like finding distances between cities or midpoints of bridges. Mastering these will make many geometry tasks much easier.

Distance and Midpoint Formulas

Distance formula for line segments

  • Calculates the length of a line segment between two points in a coordinate plane
  • Derived from the Pythagorean theorem ($a^2 + b^2 = c^2$) by considering the line segment as the hypotenuse of a right triangle
  • Formula: For points $(x_1, y_1)$ and $(x_2, y_2)$, the distance $d$ between them is $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$
  • To find the length of a line segment:
    • Identify the coordinates of the endpoints (start and end points)
    • Substitute the $x$ and $y$ values of the endpoints into the distance formula
    • Simplify the expression under the square root by squaring the differences and adding them together
    • Calculate the square root to find the final distance between the points
  • Example: Find the distance between points $(3, 4)$ and $(7, 1)$
    • $d = \sqrt{(7 - 3)^2 + (1 - 4)^2} = \sqrt{4^2 + (-3)^2} = \sqrt{16 + 9} = \sqrt{25} = 5$

Midpoint formula for coordinates

  • Determines the coordinates of the point that divides a line segment into two equal parts
  • Calculates the average of the $x$-coordinates and $y$-coordinates of the endpoints
  • Formula: For endpoints $(x_1, y_1)$ and $(x_2, y_2)$, the midpoint $M$ is $M = (\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})$
  • To find the midpoint:
    • Identify the coordinates of the endpoints of the line segment
    • Add the $x$-coordinates of the endpoints and divide the sum by 2 to find the $x$-coordinate of the midpoint
    • Add the $y$-coordinates of the endpoints and divide the sum by 2 to find the $y$-coordinate of the midpoint
    • Write the midpoint as an ordered pair $(x, y)$
  • Example: Find the midpoint of the line segment with endpoints $(-2, 5)$ and $(6, 9)$
    • $x$-coordinate of midpoint: $\frac{-2 + 6}{2} = \frac{4}{2} = 2$
    • $y$-coordinate of midpoint: $\frac{5 + 9}{2} = \frac{14}{2} = 7$
    • Midpoint: $(2, 7)$

Applications of distance and midpoint

  • Recognize when to use the distance or midpoint formula in real-world problems
  • Identify relevant information such as coordinates of points or lengths of segments
  • Apply the appropriate formula to solve the problem:
    • Distance formula for finding lengths or distances between points (cities, landmarks)
    • Midpoint formula for finding the center point of a line segment (roads, bridges)
  • Interpret the results in the context of the problem considering units of measurement (miles, kilometers)
  • Example: Two cities are located at $(120, 250)$ and $(400, 150)$ on a map with a scale of 1 unit = 10 miles. Find the distance between the cities.
    • Coordinates: $(120, 250)$ and $(400, 150)$
    • $d = \sqrt{(400 - 120)^2 + (150 - 250)^2} = \sqrt{280^2 + (-100)^2} = \sqrt{78400 + 10000} = \sqrt{88400} \approx 297$ units
    • Scale: 1 unit = 10 miles, so the actual distance is $297 \times 10 \approx 2970$ miles