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๐Ÿ“Honors Pre-Calculus Unit 8 Review

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8.6 Parametric Equations

๐Ÿ“Honors Pre-Calculus
Unit 8 Review

8.6 Parametric Equations

Written by the Fiveable Content Team โ€ข Last updated September 2025
Written by the Fiveable Content Team โ€ข Last updated September 2025
๐Ÿ“Honors Pre-Calculus
Unit & Topic Study Guides

Parametric equations offer a powerful way to describe curves and motion using a parameter. They allow us to represent complex shapes and trajectories that can't be easily expressed with standard functions. This approach opens up new possibilities for modeling and analysis.

Converting between parametric and rectangular forms is crucial for working with these equations. We can also use calculus techniques to find tangent lines, velocities, and arc lengths. Understanding how the parameter affects curve shape and position is key to mastering this topic.

Parametric Equations

Parametric to rectangular conversion

  • Parametric equations define a curve using two equations x(t)x(t) and y(t)y(t) with parameter tt (circle)
  • Convert parametric to rectangular by eliminating tt
    • Solve one equation for tt and substitute into the other
    • x(t)=t2x(t) = t^2, y(t)=t3y(t) = t^3, solve x(t)x(t) for t=xt = \sqrt{x}, substitute into y(t)y(t) to get y=x3/2y = x^{3/2}
  • Convert rectangular to parametric by introducing tt
    • Express xx and yy as functions of tt
    • y=x2y = x^2, let x(t)=tx(t) = t and y(t)=t2y(t) = t^2

Modeling with parametric equations

  • Model 2D motion with x(t)x(t) and y(t)y(t) representing position at time tt
    • Projectile launched with velocity vv at angle ฮธ\theta: x(t)=vcosโก(ฮธ)tx(t) = v\cos(\theta)t and y(t)=vsinโก(ฮธ)tโˆ’12gt2y(t) = v\sin(\theta)t - \frac{1}{2}gt^2, gg is gravity
  • Model shapes and curves
    • Cycloid (path traced by point on rolling circle): x(t)=r(tโˆ’sinโก(t))x(t) = r(t - \sin(t)) and y(t)=r(1โˆ’cosโก(t))y(t) = r(1 - \cos(t)), rr is circle radius
  • Vector-valued functions can represent parametric curves in higher dimensions

Calculus of parametric curves

  • Derivatives provide curve information
    • First derivatives dxdt\frac{dx}{dt} and dydt\frac{dy}{dt} are velocity components
    • Second derivatives d2xdt2\frac{d^2x}{dt^2} and d2ydt2\frac{d^2y}{dt^2} are acceleration components
  • Find tangent line slope using first derivatives: dy/dtdx/dt\frac{dy/dt}{dx/dt}
  • Calculate arc length with integrals: โˆซab(dxdt)2+(dydt)2dt\int_{a}^{b} \sqrt{(\frac{dx}{dt})^2 + (\frac{dy}{dt})^2} dt

Geometric interpretation of parameters

  • Parameter tt represents different quantities based on context
    • Motion problems: tt is often time
    • Shape problems: tt may be angle or proportion
  • Parameter domain determines portion of curve considered
    • Unit circle x(t)=cosโก(t)x(t) = \cos(t), y(t)=sinโก(t)y(t) = \sin(t), domain 0โ‰คtโ‰ค2ฯ€0 \leq t \leq 2\pi is one revolution
  • Parameter values affect curve shape and position
    • Cycloid equations x(t)=r(tโˆ’sinโก(t))x(t) = r(t - \sin(t)), y(t)=r(1โˆ’cosโก(t))y(t) = r(1 - \cos(t)), changing rr changes cycloid size

Advanced parametric representations

  • Polar coordinates can be expressed parametrically as x(t)=r(t)cosโก(t)x(t) = r(t)\cos(t), y(t)=r(t)sinโก(t)y(t) = r(t)\sin(t)
  • Phase plane analysis uses parametric equations to study dynamical systems
  • Parametric surfaces extend the concept to three dimensions, defining a surface with three equations x(u,v)x(u,v), y(u,v)y(u,v), and z(u,v)z(u,v)