Fiveable

๐Ÿ”ŸElementary Algebra Unit 9 Review

QR code for Elementary Algebra practice questions

9.4 Multiply Square Roots

๐Ÿ”ŸElementary Algebra
Unit 9 Review

9.4 Multiply Square Roots

Written by the Fiveable Content Team โ€ข Last updated September 2025
Written by the Fiveable Content Team โ€ข Last updated September 2025
๐Ÿ”ŸElementary Algebra
Unit & Topic Study Guides

Multiplying square roots is a key skill in algebra. It involves using the product property to combine radicands and simplify expressions. This process helps streamline calculations and solve more complex problems involving radicals.

Understanding these techniques opens doors to more advanced math concepts. By mastering multiplication of square roots, you'll be better equipped to tackle equations, simplify expressions, and work with irrational numbers in various mathematical contexts.

Multiplying Square Roots

Product property of square roots

  • States that the product of the square roots of two numbers equals the square root of the product of those numbers $\sqrt{a} \cdot \sqrt{b} = \sqrt{ab}$
    • Allows multiplying square roots by multiplying the radicands (numbers under the square root symbols)
    • $\sqrt{3} \cdot \sqrt{5} = \sqrt{3 \cdot 5} = \sqrt{15}$
  • When multiplying square roots with the same radicand, add the exponents
    • $\sqrt{a} \cdot \sqrt{a} = \sqrt{a^2} = a$
    • $\sqrt{2} \cdot \sqrt{2} = \sqrt{2^2} = 2$
  • If radicands have common factors, simplify the result by taking the square root of the common factors
    • $\sqrt{8} \cdot \sqrt{18} = \sqrt{8 \cdot 18} = \sqrt{144} = \sqrt{16 \cdot 9} = 4 \cdot 3 = 12$
    • $\sqrt{12} \cdot \sqrt{27} = \sqrt{12 \cdot 27} = \sqrt{324} = \sqrt{81 \cdot 4} = 9 \cdot 2 = 18$

Simplification of radical expressions

  • When a square root is multiplied by a coefficient, simplify by multiplying the coefficient with the radicand
    • $a\sqrt{b} = \sqrt{a^2b}$
    • $2\sqrt{3} = \sqrt{2^2 \cdot 3} = \sqrt{12}$
  • If the coefficient is a perfect square, take its square root and multiply it by the square root of the radicand
    • $4\sqrt{5} = \sqrt{4} \cdot \sqrt{5} = 2\sqrt{5}$
    • $9\sqrt{7} = \sqrt{9} \cdot \sqrt{7} = 3\sqrt{7}$
  • When multiplying expressions with coefficients and square roots, multiply the coefficients and apply the product property to the square roots
    • $(2\sqrt{3}) \cdot (3\sqrt{5}) = (2 \cdot 3) \cdot (\sqrt{3} \cdot \sqrt{5}) = 6\sqrt{15}$
    • $(4\sqrt{2}) \cdot (2\sqrt{6}) = (4 \cdot 2) \cdot (\sqrt{2} \cdot \sqrt{6}) = 8\sqrt{12} = 8 \cdot 2\sqrt{3} = 16\sqrt{3}$
  • Simplification often involves reducing the radicand to its simplest form by factoring out perfect squares

Distribution with radicals and polynomials

  • The distributive property states that $a(b + c) = ab + ac$
  • When multiplying a square root by a polynomial, distribute the square root to each term of the polynomial and then simplify
    • $\sqrt{2}(3x + 4) = \sqrt{2} \cdot 3x + \sqrt{2} \cdot 4 = 3x\sqrt{2} + 4\sqrt{2}$
    • $\sqrt{5}(2x - 3) = \sqrt{5} \cdot 2x - \sqrt{5} \cdot 3 = 2x\sqrt{5} - 3\sqrt{5}$
  • If multiplying two binomials containing square roots, use the FOIL method (First, Outer, Inner, Last) and then simplify
    • $(\sqrt{3} + 2)(\sqrt{3} - 2) = (\sqrt{3} \cdot \sqrt{3}) + (\sqrt{3} \cdot -2) + (2 \cdot \sqrt{3}) + (2 \cdot -2) = 3 - 2\sqrt{3} + 2\sqrt{3} - 4 = -1$
    • $(\sqrt{2} + 3)(\sqrt{2} + 1) = (\sqrt{2} \cdot \sqrt{2}) + (\sqrt{2} \cdot 1) + (3 \cdot \sqrt{2}) + (3 \cdot 1) = 2 + \sqrt{2} + 3\sqrt{2} + 3 = 5 + 4\sqrt{2}$

Advanced techniques for radical expressions

  • Rationalization involves eliminating radicals from the denominator of a fraction
    • Use the conjugate (the same expression with the opposite sign between terms) to multiply both numerator and denominator
  • Exponent rules are crucial when simplifying expressions with radicals
    • For example, $(\sqrt{a})^2 = a$ and $\sqrt{a^2} = |a|$