Fiveable

๐Ÿ”ŸElementary Algebra Unit 10 Review

QR code for Elementary Algebra practice questions

10.3 Solve Quadratic Equations Using the Quadratic Formula

๐Ÿ”ŸElementary Algebra
Unit 10 Review

10.3 Solve Quadratic Equations Using the Quadratic Formula

Written by the Fiveable Content Team โ€ข Last updated September 2025
Written by the Fiveable Content Team โ€ข Last updated September 2025
๐Ÿ”ŸElementary Algebra
Unit & Topic Study Guides

Quadratic equations are a cornerstone of algebra, allowing us to solve problems involving squared terms. The quadratic formula is a powerful tool that can crack any quadratic equation, no matter how tricky it looks.

Understanding the discriminant helps us predict the nature of a quadratic equation's solutions before we even solve it. This insight is crucial for tackling more complex problems and interpreting real-world scenarios modeled by quadratic equations.

Solving Quadratic Equations

Application of quadratic formula

  • Solves quadratic equations in the form $ax^2 + bx + c = 0$ where $a$, $b$, and $c$ are constants and $a \neq 0$
  • Quadratic formula: $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$
    • $a$, $b$, and $c$ are coefficients of the quadratic equation
    • $\pm$ symbol indicates two possible solutions
  • Steps to apply quadratic formula:
    1. Identify values of $a$, $b$, and $c$ in given quadratic equation
    2. Substitute values into quadratic formula
    3. Simplify expression under square root (discriminant)
    4. Calculate two possible solutions by adding and subtracting square root term
  • Example: Solve $2x^2 + 7x - 4 = 0$
    • $a = 2$, $b = 7$, $c = -4$
    • $x = \frac{-7 \pm \sqrt{7^2 - 4(2)(-4)}}{2(2)}$
    • $x = \frac{-7 \pm \sqrt{49 + 32}}{4} = \frac{-7 \pm \sqrt{81}}{4} = \frac{-7 \pm 9}{4}$
    • $x_1 = \frac{-7 + 9}{4} = \frac{1}{2}$ and $x_2 = \frac{-7 - 9}{4} = -4$

Interpretation of discriminant

  • Discriminant is expression under square root in quadratic formula: $b^2 - 4ac$
  • Value of discriminant determines nature and number of solutions for quadratic equation
    • Positive discriminant ($b^2 - 4ac > 0$): two distinct real solutions
    • Zero discriminant ($b^2 - 4ac = 0$): one repeated real solution
    • Negative discriminant ($b^2 - 4ac < 0$): no real solutions (two complex solutions)
  • Example: Determine nature and number of solutions for $3x^2 - 5x + 2 = 0$
    • $a = 3$, $b = -5$, $c = 2$
    • Discriminant = $(-5)^2 - 4(3)(2) = 25 - 24 = 1$
    • Positive discriminant, so equation has two distinct real solutions

Methods for quadratic equations

  • Factoring most efficient when:
    • Quadratic equation has integer coefficients
    • Leading coefficient ($a$) is 1 or easily factored out
    • Product of $a$ and $c$ is relatively small
  • Completing the square most efficient when:
    • Quadratic equation not easily factored
    • Leading coefficient ($a$) is 1 or easily factored out
    • Equation needs transformation into vertex form ($y = a(x - h)^2 + k$)
  • Quadratic formula most efficient when:
    • Quadratic equation not easily factored
    • Leading coefficient ($a$) not 1 and not easily factored out
    • Equation has complex ($a + bi$) or irrational ($\sqrt{2}$) solutions
  • General approach: try factoring first, then completing the square if factoring not possible or efficient, finally use quadratic formula if other methods not suitable

Quadratic Equations and Their Graphical Representation

  • Quadratic equations in standard form ($ax^2 + bx + c = 0$) represent parabolas when graphed
  • Solutions to quadratic equations (roots) correspond to x-intercepts of the parabola
  • The imaginary unit $i$ is used when the discriminant is negative, resulting in complex roots
  • The quadratic formula helps find these roots, whether real or complex