Half-life is a crucial concept in chemical kinetics, measuring the time it takes for a reactant's concentration to halve. For first-order reactions, it's constant and independent of initial concentration, making it a handy tool for predicting reaction progress.
Understanding half-life helps us grasp how quickly reactions occur and how long substances persist. It's super useful in real-world applications like drug elimination in the body and radioactive decay, helping us make sense of complex chemical processes.
Half-Life and Its Applications
Definition and significance of half-life
- Time required for reactant concentration to decrease to half its initial value
- Measures reaction rate and remains constant for first-order reactions
- Shorter half-life indicates faster reaction rate (radioactive decay of uranium-235)
- Longer half-life indicates slower reaction rate (decomposition of sucrose in solution)
- Independent of initial concentration for first-order reactions
- Crucial for predicting reaction progress and determining time required for reactant to reach specific concentration (drug elimination in the body)
Half-life vs rate constant relationship
- First-order reaction rate law: $\frac{-d[A]}{dt} = k[A]$
- $k$: rate constant
- $[A]$: reactant A concentration
- Integrated rate law: $\ln\frac{[A]_t}{[A]_0} = -kt$
- $[A]_0$: initial concentration of A
- $[A]_t$: concentration of A at time $t$
- At half-life, $[A]_t = \frac{1}{2}[A]_0$, substituting into integrated rate law:
- $\ln\frac{\frac{1}{2}[A]_0}{[A]0} = -kt{1/2}$
- $\ln\frac{1}{2} = -kt_{1/2}$
- Solving for $t_{1/2}$: $t_{1/2} = \frac{\ln 2}{k}$
- Equation relates half-life to rate constant for first-order reactions (decomposition of hydrogen peroxide)
Calculation of first-order reaction half-life
- Using equation $t_{1/2} = \frac{\ln 2}{k}$, calculate half-life if rate constant is known
- Example: $k = 0.05 \text{ s}^{-1}$, then $t_{1/2} = \frac{\ln 2}{0.05 \text{ s}^{-1}} \approx 13.9 \text{ s}$
- Half-life independent of initial concentration for first-order reactions
- Changing initial concentration does not affect half-life (decomposition of nitrogen pentoxide)
- If initial concentration and concentration at specific time are known, calculate half-life using integrated rate law
- Example: $[A]0 = 1.0 \text{ M}$, $[A]t = 0.25 \text{ M}$ at $t = 20 \text{ s}$, then $\ln\frac{0.25 \text{ M}}{1.0 \text{ M}} = -k(20 \text{ s})$, solving for $k$ and using $t{1/2} = \frac{\ln 2}{k}$ gives $t{1/2} \approx 13.9 \text{ s}$
Applications of half-life concept
- Radioactive decay follows first-order kinetics, half-life is time required for half of original amount of isotope to decay
- Amount of radioisotope remaining after certain number of half-lives: $A_t = A_0(\frac{1}{2})^n$
- $A_0$: initial amount of radioisotope
- $A_t$: amount remaining after time $t$
- $n$: number of half-lives elapsed (carbon-14 dating)
- Amount of radioisotope remaining after certain number of half-lives: $A_t = A_0(\frac{1}{2})^n$
- Drug elimination in body often follows first-order kinetics, half-life is time required for drug concentration in body to decrease by half
- Elimination rate constant determined from half-life: $k = \frac{\ln 2}{t_{1/2}}$
- Drug concentration in body after certain time calculated using integrated rate law: $[D]_t = [D]_0e^{-kt}$
- $[D]_0$: initial drug concentration
- $[D]_t$: drug concentration at time $t$ (caffeine metabolism)