Fiveable

โž—Calculus II Unit 2 Review

QR code for Calculus II practice questions

2.4 Arc Length of a Curve and Surface Area

โž—Calculus II
Unit 2 Review

2.4 Arc Length of a Curve and Surface Area

Written by the Fiveable Content Team โ€ข Last updated September 2025
Written by the Fiveable Content Team โ€ข Last updated September 2025
โž—Calculus II
Unit & Topic Study Guides

Arc length and surface area calculations are essential tools in calculus. They allow us to measure curves and rotated solids accurately. These concepts build on integration techniques, applying them to real-world problems in geometry and physics.

Understanding arc length and surface area formulas helps us analyze complex shapes. We'll explore how to set up and solve these integrals, connecting our knowledge of derivatives and integration to practical applications in measuring curved objects.

Arc Length and Surface Area

Arc length of y = f(x) curves

  • Formula calculates arc length $L$ of a curve $y = f(x)$ between points $x = a$ and $x = b$
    • $L = \int_{a}^{b} \sqrt{1 + \left(\frac{dy}{dx}\right)^2} dx$
  • Steps to calculate arc length:
    1. Find derivative of $f(x)$, denoted as $\frac{dy}{dx}$
    2. Substitute derivative into arc length formula
    3. Evaluate resulting definite integral from $a$ to $b$
  • Example: Arc length of $y = \frac{1}{3}x^{3/2}$ from $x = 0$ to $x = 8$
    • Derivative: $\frac{dy}{dx} = \frac{1}{2}\sqrt{x}$
    • Integral: $L = \int_{0}^{8} \sqrt{1 + \left(\frac{1}{2}\sqrt{x}\right)^2} dx$
    • Simplify integrand and evaluate to find arc length (exact value or approximation)
  • The concept of arc length is closely related to path length in differential geometry

Arc length of x = g(y) curves

  • Formula calculates arc length $L$ of a curve $x = g(y)$ between points $y = c$ and $y = d$
    • $L = \int_{c}^{d} \sqrt{1 + \left(\frac{dx}{dy}\right)^2} dy$
  • Steps to calculate arc length:
    1. Find derivative of $g(y)$, denoted as $\frac{dx}{dy}$
    2. Substitute derivative into arc length formula
    3. Evaluate resulting definite integral from $c$ to $d$
  • Example: Arc length of $x = \frac{1}{4}y^2$ from $y = 0$ to $y = 2$
    • Derivative: $\frac{dx}{dy} = \frac{1}{2}y$
    • Integral: $L = \int_{0}^{2} \sqrt{1 + \left(\frac{1}{2}y\right)^2} dy$
    • Simplify integrand and evaluate to find arc length (exact value or approximation)
  • Arc length can also be expressed using line integrals in more complex scenarios

Surface area of rotated solids

  • Formula for surface area $A$ of a curve $y = f(x)$ rotated around x-axis from $x = a$ to $x = b$:
    • $A = 2\pi \int_{a}^{b} f(x) \sqrt{1 + \left(\frac{dy}{dx}\right)^2} dx$
  • Formula for surface area $A$ of a curve $y = f(x)$ rotated around y-axis from $x = a$ to $x = b$:
    • $A = 2\pi \int_{a}^{b} x \sqrt{1 + \left(\frac{dy}{dx}\right)^2} dx$
  • Steps to calculate surface area:
    1. Identify curve $y = f(x)$ and axis of rotation (x-axis or y-axis)
    2. Find derivative of $f(x)$, denoted as $\frac{dy}{dx}$
    3. Substitute function and derivative into appropriate surface area formula
    4. Evaluate resulting definite integral from $a$ to $b$
  • Example: Surface area of $y = \sqrt{x}$ rotated around x-axis from $x = 0$ to $x = 1$
    • Derivative: $\frac{dy}{dx} = \frac{1}{2\sqrt{x}}$
    • Integral: $A = 2\pi \int_{0}^{1} \sqrt{x} \sqrt{1 + \left(\frac{1}{2\sqrt{x}}\right)^2} dx$
    • Simplify integrand and evaluate to find surface area (exact value or approximation)

Advanced Concepts in Curve Analysis

  • Curvilinear coordinates: A coordinate system used to describe curves and surfaces in more complex geometries
  • Gaussian curvature: A measure of the local curvature of a surface, important in differential geometry and surface analysis