Fiveable

๐Ÿ“กBioengineering Signals and Systems Unit 8 Review

QR code for Bioengineering Signals and Systems practice questions

8.3 Inverse Z-transform

๐Ÿ“กBioengineering Signals and Systems
Unit 8 Review

8.3 Inverse Z-transform

Written by the Fiveable Content Team โ€ข Last updated September 2025
Written by the Fiveable Content Team โ€ข Last updated September 2025
๐Ÿ“กBioengineering Signals and Systems
Unit & Topic Study Guides

The inverse Z-transform is a crucial tool in digital signal processing. It allows us to convert Z-domain representations back into discrete-time signals, enabling analysis and manipulation of digital systems.

This topic covers methods for finding the inverse Z-transform, including partial fraction expansion, power series, and residue methods. These techniques help break down complex Z-domain expressions into simpler terms for easier conversion to time-domain signals.

Inverse Z-Transform

Concept of inverse Z-transform

  • Converts Z-domain representation $X(z)$ back to discrete-time signal $x[n]$
    • Reverse process of Z-transform which converts discrete-time signal to Z-domain representation
  • Essential for analyzing and manipulating signals in Z-domain and converting results back to discrete-time domain
    • Allows design and analysis of discrete-time systems (digital filters, control systems)

Partial fraction expansion for Z-transforms

  • Technique used to decompose rational Z-transform expressions into sum of simpler terms
    • Rational Z-transform expression is ratio of two polynomials in $z$: $X(z) = \frac{P(z)}{Q(z)}$
  • Process involves following steps:
    1. Factorize denominator polynomial $Q(z)$ into product of linear and irreducible quadratic factors
    2. Determine form of partial fraction expansion based on factors of $Q(z)$
      • Distinct linear factors: $\frac{A_1}{z-p_1} + \frac{A_2}{z-p_2} + \cdots + \frac{A_n}{z-p_n}$
      • Repeated linear factors: $\frac{A_1}{(z-p_1)^1} + \frac{A_2}{(z-p_1)^2} + \cdots + \frac{A_m}{(z-p_1)^m}$
      • Irreducible quadratic factors: $\frac{B_1z+C_1}{(z-\alpha_1)(z-\beta_1)} + \cdots + \frac{B_kz+C_k}{(z-\alpha_k)(z-\beta_k)}$
    3. Solve for unknown coefficients ($A_i$, $B_i$, $C_i$) by equating original expression with partial fraction expansion and comparing coefficients or evaluating at specific points
  • Simplifies process of finding inverse Z-transform by breaking down expression into easier to handle terms

Methods for Finding the Inverse Z-Transform

Power series method for inverse Z-transform

  • Used to find inverse Z-transform of simple Z-domain expressions (single term, geometric series)
  • For Z-domain expression of form $X(z) = az^{-k}$, inverse Z-transform is:
    • $x[n] = a\delta[n-k]$, where $\delta[n]$ is unit impulse function
  • For Z-domain expression representing geometric series, such as $X(z) = \frac{a}{1-bz^{-1}}$, inverse Z-transform is:
    • $x[n] = ab^nu[n]$, where $u[n]$ is unit step function
  • Involves expanding Z-domain expression into infinite series and identifying corresponding discrete-time signal based on series coefficients

Residue method for inverse Z-transform

  • Powerful technique for finding inverse Z-transform of rational Z-domain expressions
  • After applying partial fraction expansion to decompose rational Z-transform expression into simpler terms, residue method can be used to find inverse Z-transform of each term
  • For simple pole at $z = p_i$, residue is:
    • $\text{Res}[X(z)]{z=p_i} = \lim{z \to p_i} (z-p_i)X(z)$
  • Inverse Z-transform of simple pole term $\frac{A_i}{z-p_i}$ is:
    • $x_i[n] = A_ip_i^nu[n]$
  • For pole of order $m$ at $z = p_i$, residue is:
    • $\text{Res}[X(z)]{z=p_i} = \frac{1}{(m-1)!} \lim{z \to p_i} \frac{d^{m-1}}{dz^{m-1}} [(z-p_i)^mX(z)]$
  • Inverse Z-transform of repeated pole term $\frac{A_j}{(z-p_i)^j}$ is:
    • $x_{ij}[n] = A_j\frac{n^{j-1}}{(j-1)!}p_i^nu[n]$
  • Total inverse Z-transform is sum of inverse Z-transforms of all individual terms obtained from partial fraction expansion