Nuclear physics explores the fundamental processes of atomic nuclei. This includes fission, fusion, and radioactive decay, which involve changes in nuclear structure and energy release.
These processes are governed by conservation laws and the strong nuclear force. Understanding them is crucial for applications like nuclear energy, weapons, and medical treatments.
Physical Properties of Nuclear Interactions

Strong Force in Nucleons
The strong nuclear force is the fundamental interaction that holds nucleons (protons and neutrons) together in atomic nuclei.
- Acts over extremely short distances (approximately 1-3 femtometers) but is incredibly powerful
- Overcomes the electromagnetic repulsion between positively charged protons
- Becomes negligible beyond about 2.5 femtometers, explaining why larger nuclei can become unstable
- Exhibits the property of "saturation" - each nucleon only interacts strongly with its nearest neighbors
The strong force is what makes nuclear reactions possible, as it provides the binding energy that can be released during fission and fusion processes.
Conservation of Nucleon Number
During any nuclear reaction, the total number of nucleons (protons + neutrons) remains constant, following a fundamental conservation law.
- In equations, this is represented by ensuring the sum of mass numbers (A) is equal on both sides
- When a neutron transforms into a proton during beta decay, the total nucleon count stays the same
- This conservation principle helps us balance nuclear equations and predict reaction products
- Example: In the fusion reaction , the total nucleon count is 5 on both sides
Conservation Laws in Nuclear Reactions
Nuclear reactions obey the same fundamental conservation laws that govern all physical processes.
- Energy conservation includes both rest mass energy and kinetic energy of all particles
- Momentum conservation determines the directions and speeds of reaction products
- Charge conservation requires the total electric charge to remain constant
- Angular momentum conservation affects the possible quantum states of reaction products
These conservation laws provide powerful tools for analyzing and predicting the outcomes of nuclear reactions.
Mass-Energy Equivalence
Einstein's famous equation is particularly relevant in nuclear physics, as it explains how energy is released in nuclear reactions.
- The binding energy of a nucleus represents the energy equivalent of the mass difference between:
- The actual nucleus
- The sum of its constituent protons and neutrons if separated
- This "mass defect" (Δm) multiplied by gives the binding energy
- In fission and fusion, the products have a slightly lower total mass than the reactants
- This small mass difference (typically <1%) converts to enormous energy release due to the large value of
Energy Release in Nuclear Processes
Nuclear reactions release energy in various forms, with the total energy determined by the mass-energy equivalence.
- Kinetic energy of reaction products (alpha particles, fission fragments, etc.)
- Electromagnetic radiation (gamma rays)
- Neutrinos (which carry away energy but rarely interact with matter)
- The energy released per nucleon is greatest for nuclei with mass numbers around 56 (iron)
- This explains why fusion of light elements and fission of heavy elements both release energy
The energy yield from nuclear reactions is millions of times greater than chemical reactions involving the same mass of material.
Nuclear Fusion
Nuclear fusion occurs when two light nuclei combine to form a heavier nucleus, releasing energy in the process.
- Requires overcoming the Coulomb barrier (electrostatic repulsion between positively charged nuclei)
- Typically occurs at extremely high temperatures (millions of degrees) where particles have enough kinetic energy
- Powers stars like our Sun through hydrogen fusion cycles
- Fusion reactions like deuterium-tritium () release about 17.6 MeV of energy
Fusion is considered a promising future energy source because it produces no greenhouse gases or long-lived radioactive waste, and its fuel (hydrogen isotopes) is abundant.
Nuclear Fission
Nuclear fission is the splitting of a heavy nucleus into two or more lighter nuclei, accompanied by energy release.
- Most commonly occurs with heavy elements like uranium and plutonium
- The fission products have greater binding energy per nucleon than the original nucleus
- Typically releases 2-3 neutrons per fission event, enabling chain reactions
- A single uranium-235 fission event releases approximately 200 MeV of energy
The controlled chain reaction in nuclear reactors provides steady energy production, while uncontrolled chain reactions power nuclear weapons.
Spontaneous vs Induced Fission
Fission can occur either spontaneously or through external induction, depending on the stability of the nucleus.
- Spontaneous fission:
- Occurs naturally in very heavy, unstable nuclei
- Happens without external intervention
- Example: Uranium-238 occasionally undergoes spontaneous fission with a half-life of about 4.5 billion years
- Induced fission:
- Triggered by the absorption of a particle (usually a neutron)
- The compound nucleus formed becomes unstable and splits
- Example: Uranium-235 readily undergoes induced fission when it captures a thermal (slow) neutron
Most nuclear power applications rely on induced fission, as it can be controlled through neutron moderation and absorption.
Radioactive Decay
Spontaneous Nuclear Transformation
Radioactive decay is a spontaneous process where unstable nuclei transform to achieve greater stability.
- Occurs due to imbalances in the proton-to-neutron ratio or excessive nuclear energy
- The exact moment when a specific nucleus will decay cannot be predicted
- For a large sample, the decay follows statistical patterns with predictable rates
- Common decay modes include alpha, beta, and gamma emission, each with distinct properties
The probabilistic nature of radioactive decay is a fundamental example of quantum mechanical behavior in macroscopic systems.
Half-life of Radioactive Materials
The half-life is a key characteristic of radioactive materials that determines how quickly they decay.
- Defined as the time required for half of the radioactive nuclei in a sample to decay
- Each isotope has a unique half-life, ranging from microseconds to billions of years
- After one half-life, 50% remains; after two half-lives, 25% remains; after three, 12.5% remains
- The mathematical relationship is given by where:
- is the remaining number of radioactive nuclei
- is the initial number
- is the elapsed time
- is the half-life
Half-lives are used in carbon dating, medical diagnostics, and determining the safety periods for radioactive waste storage.
Decay Constant
The decay constant (λ) represents the probability per unit time that a radioactive nucleus will decay.
- Related to half-life by the equation
- Used in the exponential decay equation
- The activity (decay rate) of a sample is given by , measured in becquerels (Bq) or curies (Ci)
- The larger the decay constant, the shorter the half-life and the more radioactive the sample
The decay constant provides a convenient way to calculate the number of radioactive nuclei remaining after any given time period.
Practice Problem 1: Nuclear Binding Energy
A helium-4 nucleus (alpha particle) has a mass of 4.0026 u, while the mass of a proton is 1.0073 u and the mass of a neutron is 1.0087 u. Calculate the binding energy of the helium-4 nucleus in MeV. (1 u = 931.494 MeV/c²)
Solution
First, we need to find the mass defect by calculating the difference between the sum of the constituent particles and the actual helium nucleus:
Mass of constituent particles = 2(proton mass) + 2(neutron mass) Mass of constituent particles = 2(1.0073 u) + 2(1.0087 u) = 2.0146 u + 2.0174 u = 4.0320 u
Mass defect = Sum of constituent masses - Actual nucleus mass
Mass defect = 4.0320 u - 4.0026 u = 0.0294 u
Now we convert this mass defect to energy using E = mc²: Binding energy = (Mass defect) × (931.494 MeV/u) Binding energy = 0.0294 u × 931.494 MeV/u = 27.39 MeV
Therefore, the binding energy of the helium-4 nucleus is approximately 27.39 MeV.
Practice Problem 2: Radioactive Decay
A sample of radioactive material has an initial activity of 800 Bq. After 30 days, the activity has decreased to 100 Bq. Calculate (a) the decay constant and (b) the half-life of this radioactive isotope.
Solution
We can use the exponential decay equation to solve this problem:
Where:
- is the final activity (100 Bq)
- is the initial activity (800 Bq)
- is the decay constant
- is the time elapsed (30 days)
(a) To find the decay constant:
Taking the natural logarithm of both sides: day⁻¹
(b) To find the half-life, we use the relationship between decay constant and half-life: days
Therefore, the decay constant is 0.0693 day⁻¹ and the half-life is 10 days.
Practice Problem 3: Nuclear Fission
In the fission of uranium-235, a common reaction produces krypton-92, barium-141, and neutrons:
How many neutrons (x) are produced in this reaction?
Solution
To solve this problem, we need to apply the conservation of nucleon number. The total number of nucleons (protons + neutrons) must be the same on both sides of the equation.
Left side:
- Uranium-235: 235 nucleons
- Neutron: 1 nucleon
- Total: 236 nucleons
Right side:
- Krypton-92: 92 nucleons
- Barium-141: 141 nucleons
- x neutrons: x nucleons
- Total: 92 + 141 + x = 233 + x nucleons
Setting these equal: 236 = 233 + x x = 3
Therefore, 3 neutrons are produced in this fission reaction. This is significant because these neutrons can go on to cause additional fission events, potentially leading to a chain reaction.
Frequently Asked Questions
What's the difference between nuclear fission and nuclear fusion?
Nuclear fission and fusion are opposite ways nuclei change, but both follow the CED constraints: conservation of nucleon number, conservation of energy/momentum, and mass–energy equivalence (E = mc^2). - Fission: a heavy nucleus (like U-235 or Pu-239) splits into two or more smaller nuclei + neutrons. Some nuclear binding energy is released as kinetic energy and photons because the products have a higher binding energy per nucleon (mass defect → energy). Fission can be spontaneous or neutron-initiated; if emitted neutrons induce more fissions you can get a chain reaction (critical mass matters). (CED: 15.7.A.6–8) - Fusion: two or more light nuclei combine to form a heavier nucleus. Fusion releases energy when the resulting nucleus has greater binding energy per nucleon than the reactants (again mass → energy). Fusion requires extreme temperatures/pressures to overcome the Coulomb barrier (strong force acts at nuclear scales). (CED: 15.7.A.6, 15.7.A.1, 15.7.A.4–5) Both release energy via kinetic energy of products and photons; both are constrained by conservation laws and describable using mass–energy equivalence. For quick review, see the Topic 15.7 study guide (https://library.fiveable.me/ap-physics-2-revised/unit-7/7-fission-fusion-and-nuclear-decay/study-guide/nVULWHgdGjkiGhbI). For unit context and extra practice, check Unit 15 (https://library.fiveable.me/ap-physics-2-revised/unit-15) and the practice problem bank (https://library.fiveable.me/practice/ap-physics-2-revised).
How does radioactive decay actually work and why can't we predict when one atom will decay?
Radioactive decay is a quantum, spontaneous change of an unstable nucleus into a different nucleus (often emitting an alpha particle, beta particle, or gamma photon). Whether a nucleus is unstable depends on binding energy, the strong force, and conservation laws (nucleon number, energy, momentum). We can’t predict when a single nucleus will decay because decay is inherently probabilistic—quantum mechanics gives only a decay constant λ (or half-life t1/2 with λ = ln2 / t1/2) that sets the probability per unit time. For large samples the randomness averages out and you get exponential decay: N = N0 e^(−λt), so half-life and decay rates are predictable for ensembles even though individual events are not (CED 15.7.B.1 and 15.7.B.2). If you want more AP-aligned review of these ideas, check the Topic 15.7 study guide (https://library.fiveable.me/ap-physics-2-revised/unit-7/7-fission-fusion-and-nuclear-decay/study-guide/nVULWHgdGjkiGhbI) and the unit overview (https://library.fiveable.me/ap-physics-2-revised/unit-15). For lots of practice problems, see (https://library.fiveable.me/practice/ap-physics-2-revised).
What is the strong nuclear force and why does it only work at really short distances?
The strong nuclear force is the fundamental interaction that holds protons and neutrons (nucleons) together in the nucleus. It’s what provides the nuclear binding energy that overcomes the electrostatic repulsion between positively charged protons (CED 15.7.A.1, binding energy/BED ideas). Why only short range? There are two useful ways to think about it: - At the quark level the force is carried by gluons (quantum chromodynamics). Gluons cause “color confinement,” so the color force doesn’t spread out the way electric force does—it effectively binds quarks tightly and doesn’t produce a long-range pull between separate nuclei. - The residual strong force between whole nucleons is effectively mediated by massive particles (mesons). Because those carriers have mass, the force falls off very rapidly with distance (exponentially), so the strong force is only significant at nuclear distances (~1–3 fm, 10^-15 m). Net result: inside the nucleus the strong force dominates and gives binding energy; beyond a few femtometers it drops away and electromagnetic repulsion wins, which matters for fission, fusion, and decay (see Topic 15.7 study guide for more: https://library.fiveable.me/ap-physics-2-revised/unit-7/7-fission-fusion-and-nuclear-decay/study-guide/nVULWHgdGjkiGhbI). For extra practice on related AP problems, check the unit practice set (https://library.fiveable.me/practice/ap-physics-2-revised).
I'm confused about half-life - if half the atoms decay in one half-life, why don't they all decay in two half-lives?
Think of half-life as a statistical rule for a large group, not a timetable for each atom. Radioactive decay is random: any given nucleus has a certain probability per second (the decay constant λ) of decaying, but you can’t predict when an individual one will go. For a large sample the number follows exponential decay: N = N0 e^{−λt}, and λ = ln 2 / t1/2. After one half-life N = N0/2; after two half-lives N = N0/4 (not zero) because each remaining nucleus still only has the same probability to decay in the next interval. So “half the atoms decay every half-life” means the expected fraction decays, not that the sample is exhausted in a fixed number of steps. This probabilistic, exponential behavior is exactly what the CED calls radioactive decay and half-life (15.7.B.1–B.2). For a quick refresher, check the Topic 15.7 study guide (https://library.fiveable.me/ap-physics-2-revised/unit-7/7-fission-fusion-and-nuclear-decay/study-guide/nVULWHgdGjkiGhbI) and try practice problems (https://library.fiveable.me/practice/ap-physics-2-revised).
Can someone explain E=mc² in simple terms and how it relates to nuclear reactions?
E = mc^2 means mass and energy are the same thing in different forms: a tiny amount of mass m can be converted into a huge amount of energy E because c^2 (speed of light squared) is huge. In nuclear physics this shows up as mass–energy equivalence (CED 15.7.A.4). In fission or fusion, the total mass of the products is a little different from the mass of the starting nuclei. That “missing” mass becomes released energy (or vice versa)—usually as kinetic energy of particles or as photons (CED 15.7.A.5). Fusion in the Sun releases energy because combining light nuclei makes a more tightly bound nucleus with less mass (binding energy released, CED 15.7.A.1, 15.7.A.6). Fission of heavy nuclei can do the same if products have higher total binding energy per nucleon (CED 15.7.A.7–8). For AP-style review, see the Topic 15.7 study guide (https://library.fiveable.me/ap-physics-2-revised/unit-7/7-fission-fusion-and-nuclear-decay/study-guide/nVULWHgdGjkiGhbI) and try practice problems (https://library.fiveable.me/practice/ap-physics-2-revised).
Why does nuclear fusion release so much energy if you're combining things instead of breaking them apart?
Because nuclear binding energy per nucleon isn’t the same for all nuclei, combining very light nuclei (like H isotopes) into a heavier nucleus can make the result more tightly bound. “More tightly bound” means the final nucleus has less total mass-energy than the two separate nuclei—that missing mass is the mass defect and gets released as energy via E = mc^2. The strong nuclear force is what provides that binding at short ranges (CED 15.7.A.1, 15.7.A.4). So fusion releases energy when the product has a higher binding energy per nucleon than the reactants; the excess shows up as kinetic energy of products and photons (15.7.A.5). Fission also releases energy for heavy nuclei because splitting them moves products toward the peak binding-energy-per-nucleon curve. For more review on these ideas (binding energy, mass–energy equivalence, conservation laws), see the Topic 15.7 study guide (https://library.fiveable.me/ap-physics-2-revised/unit-7/7-fission-fusion-and-nuclear-decay/study-guide/nVULWHgdGjkiGhbI) and the Unit 15 overview (https://library.fiveable.me/ap-physics-2-revised/unit-15). For extra practice, check the AP Physics 2 practice problems (https://library.fiveable.me/practice/ap-physics-2-revised).
What's the decay constant and how do I use it in calculations?
The decay constant λ is the probability per unit time that any single nucleus will decay. It shows up in the exponential decay law: N = N0 e^(−λt), where N0 is the initial number of nuclei and N is the number left after time t. You can rearrange to solve for anything you need: λ = −(1/t) ln(N/N0) or t = (1/λ) ln(N0/N). The half-life t1/2 is related: λ = ln 2 / t1/2. The activity (decay rate) is A = −dN/dt = λN (units: s^−1). Quick example: if t1/2 = 5 days, λ = ln2/5 ≈ 0.1386 day^−1. After 10 days N = N0 e^(−0.1386·10) = N0 e^(−1.386) ≈ 0.25 N0 (two half-lives). These are exactly the CED equations for Topic 15.7.B (use λ to predict remaining nuclei or age a sample). For more review and practice problems, see the Topic 15.7 study guide (https://library.fiveable.me/ap-physics-2-revised/unit-7/7-fission-fusion-and-nuclear-decay/study-guide/nVULWHgdGjkiGhbI) and the unit practice set (https://library.fiveable.me/practice/ap-physics-2-revised).
How do scientists use radioactive decay to figure out how old fossils and rocks are?
Scientists date fossils and rocks by measuring radioactive decay of unstable isotopes. A sample contains a parent isotope that decays into a daughter isotope at a predictable exponential rate: N = N0 e^(−λt), where λ = ln2 / t1/2 (CED 15.7.B). You measure how much parent (or daughter) is left now, estimate the original amount (N0) or use a parent/daughter ratio, and solve for t: t = (1/λ) ln(N0/N). Different isotopes fit different timescales (e.g., C-14 for ~10^4–10^5 years, uranium–lead for millions–billions), because half-lives vary hugely (CED 15.7.B.3). On the AP exam you should be ready to use the exponential decay law and the λ ↔ t1/2 relation in calculations (CED 15.7.B.1–2). For a focused review, see the Topic 15.7 study guide (https://library.fiveable.me/ap-physics-2-revised/unit-7/7-fission-fusion-and-nuclear-decay/study-guide/nVULWHgdGjkiGhbI) and practice problems (https://library.fiveable.me/practice/ap-physics-2-revised).
I don't understand why some nuclei undergo fission spontaneously but others need energy input - what determines this?
Whether a nucleus fissions spontaneously or needs input comes down to binding energy and the reaction Q-value. If splitting a nucleus into fragments yields products whose total mass is less than the original (so Δm < 0), the mass-energy difference appears as released energy (Q > 0) and fission can be energetically favorable—it may occur spontaneously or after a small perturbation. If the fragments have higher total mass (Q < 0), you must supply energy to make fission happen. Two practical points for AP-style thinking (use CED vocabulary): the strong force and binding energy per nucleon determine stability; heavy nuclei with relatively low binding energy per nucleon (like some isotopes of uranium and plutonium) can have exothermic fission once a neutron is absorbed. Whether that neutron capture triggers fission also depends on nuclear structure (fissile vs. just fissionable), neutron energy, and conservation laws (nucleon number, energy/momentum). For more review, see the Topic 15.7 study guide (https://library.fiveable.me/ap-physics-2-revised/unit-7/7-fission-fusion-and-nuclear-decay/study-guide/nVULWHgdGjkiGhbI) and the Unit 15 overview (https://library.fiveable.me/ap-physics-2-revised/unit-15). For extra practice problems, check Fiveable’s practice set (https://library.fiveable.me/practice/ap-physics-2-revised).
What happens to all the energy that gets released during nuclear reactions?
Short answer: all the energy released in a nuclear reaction shows up as other measurable energy—mostly as kinetic energy of the reaction products and as photons (gamma rays) —and it obeys conservation of energy (including mass–energy equivalence, E = mc^2). Explanation: when a nucleus fissions, fuses, or decays, the total rest mass can change; the “missing” mass becomes energy (15.7.A.4). That energy appears as high kinetic energy of fragments and emitted particles (neutrons, alpha/beta particles), as gamma photons, and sometimes as neutrino energy. In reactors or samples that stay nearby, that particle energy quickly becomes thermal energy (heating the surroundings). Momentum is also conserved, so products move fast. AP-relevant facts: memorize E = mc^2, that energy shows up as kinetic energy or photons (15.7.A.4–A.5), and apply conservation laws for problems. For review and practice, see the Topic 15.7 study guide (https://library.fiveable.me/ap-physics-2-revised/unit-7/7-fission-fusion-and-nuclear-decay/study-guide/nVULWHgdGjkiGhbI) and try problems at Fiveable Practice (https://library.fiveable.me/practice/ap-physics-2-revised).
How do I solve problems using the equation N = N₀e^(-λt) step by step?
Use N = N0 e^{-λt} exactly the way you’d use any exponential decay—isolate the unknown, take natural logs, and plug in numbers. Step-by-step: 1. Identify what you know: N0 (initial nuclei), N (remaining nuclei), and either λ (decay constant) or t (time). If you’re given half-life t1/2, get λ = ln 2 / t1/2 (CED 15.7.B.1.iii). 2. Start with N = N0 e^{-λt}. Divide both sides by N0: N/N0 = e^{-λt}. 3. Take natural log: ln(N/N0) = -λt. This is the derived equation in the CED. 4. Solve for the unknown: - If solving for t: t = -[1/λ] ln(N/N0). - If solving for λ: λ = -[1/t] ln(N/N0). - If solving for N: N = N0 e^{-λt} (just compute). 5. Keep units consistent (t in seconds or years to match λ). Check signs: ln(N/N0) is negative when N < N0, so t and λ come out positive. Quick example: N0 = 1000, N = 250, find t if λ = 0.693/day (half-life 1 day). ln(250/1000)=ln(0.25)=-1.386 → t = -(-1.386)/0.693 = 2 days. This form and the ln-derivation show up on AP free-response and multiple-choice (practice in CED Topic 15.7). For more review and practice problems, check the Topic 15.7 study guide (https://library.fiveable.me/ap-physics-2-revised/unit-7/7-fission-fusion-and-nuclear-decay/study-guide/nVULWHgdGjkiGhbI) and the unit practice bank (https://library.fiveable.me/practice/ap-physics-2-revised).
Why is nuclear fusion so hard to achieve on Earth if it happens naturally in stars?
Fusion happens a lot in stars because gravity gives enormous pressure and temperature so nuclei can get close enough for the strong force to bind them. On Earth it’s hard because positively charged nuclei repel each other (Coulomb barrier). To overcome that repulsion you need very high kinetic energy—temperatures of millions of kelvins—and/or very high densities and long confinement times so collisions happen frequently. Achieving all three (temperature, density, confinement) so that net energy comes out is tough: you either need magnetic confinement (tokamaks) or inertial confinement (lasers), both of which struggle with instabilities, material damage from high-energy neutrons, and engineering losses. The Lawson criterion summarizes the required product of density × confinement time × temperature for net gain. For AP, focus on the roles of the strong force vs. electrostatic repulsion, mass–energy equivalence (E = mc^2) in energy release, and why extreme conditions (not present on Earth naturally) are needed (see the Topic 15.7 study guide for a concise review: https://library.fiveable.me/ap-physics-2-revised/unit-7/7-fission-fusion-and-nuclear-decay/study-guide/nVULWHgdGjkiGhbI). For extra practice, try problems at (https://library.fiveable.me/practice/ap-physics-2-revised).
What's the difference between alpha, beta, and gamma decay and which one releases the most energy?
Alpha: nucleus emits a 4He nucleus (2 protons + 2 neutrons). Mass number A drops by 4 and atomic number Z drops by 2. Alpha particles are heavy and carry a lot of kinetic energy (typically a few MeV), so they deposit energy locally. Beta: a neutron converts to a proton + electron (β−) or a proton converts to a neutron + positron (β+). Z changes by ±1 while A stays the same. The emitted beta particle plus an antineutrino/neutrino share the decay energy; typical beta energies are up to a few MeV but are often spread over a spectrum. Gamma: an excited nucleus emits a high-energy photon (γ). A and Z don’t change; gamma carries away discrete photon energies (keV–MeV) to get the nucleus to a lower energy state. Which releases the most energy? It depends on the isotope and specific decay, but typically alpha decays release the largest kinetic energy per decay (a few MeV) because of big changes in binding energy. Gamma rays can be very energetic too, but they’re usually “leftover” de-excitation energy and often smaller than the alpha Q-value for heavy nuclei. Remember conservation of energy/mass (E = mc^2) and conservation of nucleon number when predicting products (see the Topic 15.7 study guide for AP-aligned details: https://library.fiveable.me/ap-physics-2-revised/unit-7/7-fission-fusion-and-nuclear-decay/study-guide/nVULWHgdGjkiGhbI). For extra practice, hit the AP Physics 2 problems (https://library.fiveable.me/practice/ap-physics-2-revised).
I missed the lab on radioactive decay - what were we supposed to learn about exponential decay curves?
You were supposed to see that radioactive decay follows an exponential law and how to work with it on graphs and problems. Key points from the CED: N(t) = N0 e^{−λt}, λ = ln 2 / t1/2, and ln(N/N0) = −λt. That means: - The number of undecayed nuclei drops by half every t1/2 (half-life), but when a single nucleus decays is unpredictable—decay is probabilistic (15.7.B.1.i–iii). - On a semi-log plot (ln N vs. t) the data are linear with slope −λ. Use that slope to find λ and then t1/2 (useful for AP free-response and MCQs; see sample MCQ #4 in the CED). - Different isotopes have hugely different half-lives—memorize the relationships, not specific numbers. If you want a quick refresher, check the Topic 15.7 study guide (https://library.fiveable.me/ap-physics-2-revised/unit-7/7-fission-fusion-and-nuclear-decay/study-guide/nVULWHgdGjkiGhbI) and practice problems for extra decay-curve exercises (https://library.fiveable.me/practice/ap-physics-2-revised).
How does conservation of nucleon number work in nuclear reactions and why is it important?
Conservation of nucleon number means the total number of nucleons (protons + neutrons, i.e., the mass number A) is the same before and after any nuclear reaction. It’s a constraint on possible reactions (CED 15.7.A.2). For example, in a typical fission: U-235 + n → Ba-141 + Kr-92 + 3 n Check A: 235 + 1 = 141 + 92 + 3·1 = 236, so nucleon number is conserved. In beta decay (C-14 → N-14 + e- + ν̄) the mass number stays 14 even though a neutron becomes a proton (charge changes but nucleon count does not). Why it matters: it eliminates impossible reactions and helps you balance nuclear equations alongside conservation of charge, energy (including E = mc^2), and momentum (CED 15.7.A.3–A.5). On the AP exam you’ll use nucleon-number conservation to check or construct nuclear equations and to reason about decay chains and fission/fusion outcomes. For a focused review, see the Topic 15.7 study guide (https://library.fiveable.me/ap-physics-2-revised/unit-7/7-fission-fusion-and-nuclear-decay/study-guide/nVULWHgdGjkiGhbI). For extra practice problems, try the AP Physics 2 practice set (https://library.fiveable.me/practice/ap-physics-2-revised).